Write a Modular C Programming code to find out the count of apple and orange fruits, which will fall on the Roof of Ram’s house.
Ram’s house has an apple tree and an orange tree. In the diagram below, the red region denotes his house, where s is the start point, and t is the endpoint. The apple tree is to the left of his house, and the orange tree is to its right. You can assume the trees are located on a single point, where the apple tree is at point a, and the orange tree is at point b.
When a fruit falls from its tree, it lands d units of distance from its tree of origin along the x-axis. A negative value of d means the fruit fell d units to the tree’s left, and a positive value of d means it falls d units to the tree’s right. Given the value of d for 3 apples and 3 oranges, determine how many apples and oranges will fall on Ram’s house (i.e., in the inclusive range [s,t]?
ANALYSIS:
- In the given problem we need to find out the count of apple and orange fruits, which will fall on the roof of Ram’s house.
- Variables ‘s’ & ‘t’ represents the roof width of the house.
- Get the distance ‘d’ of fruit from the corresponding tree.
- Check whether ‘d’ is in between ‘s’ & ‘t’ so that fruit falls on the roof and increment the counter.
We must repeat steps 3 and 4 for all distances ‘d’ of fruits.
So we need to do a repetition of operations as mentioned in steps 3 and 4.
Input Format
s t – width of Ram’s house roof (range)
a b – points on the x-axis where the apple and orange trees are there in the house yard.
m n – number of apples and oranges fall from respective trees.
d d d . . . – a distance of each apple filling.
d d d . . . – a distance of each orange falling.
Constraints
1 ≤ s,t, a, b, m, n ≤ 100000
-100000 ≤ d ≤ 100000
a < s < t < b
A negative value of d means the fruit falls d units to the tree’s left, and a positive value of d means it falls d units to the tree’s right.
Output Format
Counts of apples and oranges fall on Ram’s house.
Sample Input 0
7 11
5 15
3 2
-2 2 1
5 -6
Sample Output 0
Apple count = 1
Orange count = 1
Sample Input 1
7 11
8 15
Sample Output 1
Invalid input
Sample Input 2
15 20
3 30
5 5
10 11 12 13 14
-10 -11 -12 -13 -14
Sample Output 2
Apple count = 3
Orange count = 5Refer : C Programming HackerRank all solutions for Loops | Arrays | strings
CODE:
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#include<math.h>
int main() {
int i,s,t,a,b,x,y,z,w,m,n,d1[100],d2[100],count=0,count1=0;
scanf("%d%d",&s,&t);
scanf("%d%d",&a,&b);
scanf("%d%d",&m,&n);
if(s>a&&t<b&&t>s)
{
for(i=0;i<m;i++)
{
scanf("%d",&d1[i]);
}
for(i=0;i<n;i++)
{
scanf("%d",&d2[i]);
}
for(i=0;i<m;i++)
{
if(d1[i]>0)
{
x=s-a;
w=t-a;
if(d1[i]>=x&&d1[i]<=w)
{
count++;
}
}
}
for(i=0;i<n;i++)
{
if(d2[i]<0)
{
y=t-b;
z=s-b;
if(d2[i]<=y&&d2[i]>=z)
{
count1++;
}
}
}
printf("Apple count = %d\n",count);
printf("Orange count = %d",count1);
}
else
printf("Invalid input");
}
OUTPUT
Congratulations, you passed the sample test case. Click the Submit Code button to run your code against all the test cases. Input (stdin) 7 11 5 15 3 2 -2 2 1 5 -6 Your Output (stdout) Apple count = 1 Orange count = 1 Expected Output Apple count = 1 Orange count = 1
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