C Programming – HackerRank Solution | Computing series |

(HackerRank) Write a Modular C Programming code to solve the Computing series, Compute the Harmonic progression series (1 + 1/2 + 1/3 + …) up to the nth term.

If inverse of a sequence follows rule of an A.P i.e, Arithmetic progression, then it is said to be in Harmonic Progression.

In general, the terms in a harmonic progression can be denoted as : 1/a, 1/(a + d), 1/(a + 2d), 1/(a + 3d) …. 1/(a + nd).

As Nth term of AP is given as ( a + (n – 1)d).

Hence, Nth term of harmonic progression is reciprocal of Nth term of AP, which is : 1/(a + (n – 1)d)

where “a” is the 1st term of AP and “d” is the common difference.


Compute the Harmonic progression series (1 + 1/2 + 1/3 + …) upto nth term.

Input Format

n is number of terms.


1 <= n <=10000

Output Format

sum of Harmonic Progression series upto n terms.

Sample Input 0


Sample Output 0

Harmonic Progression is 2.283333

Sample Input 1


Sample Output 1

Invalid input

Sample Input 2


Sample Output 2

Invalid input

Refer : C Programming HackerRank all solutions for Loops | Arrays | strings




void harmo(int n)
    double sum=0;
    double i;
    printf("Harmonic Progression is %lf\n",sum);

int main()
    int n;
        printf("Invalid input");
    return 0;


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Input (stdin)

Your Output (stdout)

Harmonic Progression is 2.283333
Expected Output

Harmonic Progression is 2.283333


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