(HackerRank) Write a Modular C Programming code to solve the Computing series, Compute the Harmonic progression series (1 + 1/2 + 1/3 + …) up to the nth term.
If inverse of a sequence follows rule of an A.P i.e, Arithmetic progression, then it is said to be in Harmonic Progression.
In general, the terms in a harmonic progression can be denoted as : 1/a, 1/(a + d), 1/(a + 2d), 1/(a + 3d) …. 1/(a + nd).
As Nth term of AP is given as ( a + (n – 1)d).
Hence, Nth term of harmonic progression is reciprocal of Nth term of AP, which is : 1/(a + (n – 1)d)
where “a” is the 1st term of AP and “d” is the common difference.
TASK:
Compute the Harmonic progression series (1 + 1/2 + 1/3 + …) upto nth term.
Input Format
n is number of terms.
Constraints
1 <= n <=10000
Output Format
sum of Harmonic Progression series upto n terms.
Sample Input 0
5
Sample Output 0
Harmonic Progression is 2.283333
Sample Input 1
0
Sample Output 1
Invalid input
Sample Input 2
-10
Sample Output 2
Invalid inputRefer : C Programming HackerRank all solutions for Loops | Arrays | strings
CODE:
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#include<math.h>
void harmo(int n)
{
double sum=0;
double i;
for(i=1;i<=n;i++)
{
sum=sum+(1/i);
}
printf("Harmonic Progression is %lf\n",sum);
}
int main()
{
int n;
scanf("%d",&n);
if(n<1)
{
printf("Invalid input");
exit(0);
}
harmo(n);
return 0;
}
OUTPUT
Congratulations, you passed the sample test case. Click the Submit Code button to run your code against all the test cases. Input (stdin) 5 Your Output (stdout) Harmonic Progression is 2.283333 Expected Output Harmonic Progression is 2.283333
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