**(HackerRank) Write a Modular C Programming code to solve the Computing series, Compute the Harmonic progression series (1 + 1/2 + 1/3 + …) up to the nth term.**

If inverse of a sequence follows rule of an A.P i.e, Arithmetic progression, then it is said to be in Harmonic Progression.

In general, the terms in a harmonic progression can be denoted as : 1/a, 1/(a + d), 1/(a + 2d), 1/(a + 3d) …. 1/(a + nd).

As Nth term of AP is given as ( a + (n – 1)d).

Hence, Nth term of harmonic progression is reciprocal of Nth term of AP, which is : 1/(a + (n – 1)d)

where “a” is the 1st term of AP and “d” is the common difference.

TASK:

Compute the Harmonic progression series (1 + 1/2 + 1/3 + …) upto nth term.

**Input Format**

n is number of terms.

**Constraints**

1 <= n <=10000

**Output Format**

sum of Harmonic Progression series upto n terms.

**Sample Input 0**

```
5
```

**Sample Output 0**

```
Harmonic Progression is 2.283333
```

**Sample Input 1**

```
0
```

**Sample Output 1**

```
Invalid input
```

**Sample Input 2**

```
-10
```

**Sample Output 2**

`Invalid input`

**Refer :** C Programming HackerRank all solutions for Loops | Arrays | strings

**CODE:**

#include<stdio.h> #include<stdlib.h> #include<string.h> #include<math.h> void harmo(int n) { double sum=0; double i; for(i=1;i<=n;i++) { sum=sum+(1/i); } printf("Harmonic Progression is %lf\n",sum); } int main() { int n; scanf("%d",&n); if(n<1) { printf("Invalid input"); exit(0); } harmo(n); return 0; }

**OUTPUT**

Congratulations, you passed the sample test case. Click the Submit Code button to run your code against all the test cases. Input (stdin) 5 Your Output (stdout) Harmonic Progression is 2.283333 Expected Output Harmonic Progression is 2.283333

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