C Programming – HackerRank Solution | Divisor summation 1 |

(HackerRank) Write a Modular C Programming code to solve Divisor summation 1, Given a natural number n output the summation of all its proper divisors.

Given a natural number n output the summation of all its proper divisors.

Definition: A proper divisor of a natural number is the divisor that is strictly less than the number. e.g. number 20 has 5 proper divisors: 1, 2, 4, 5, 10, and the divisor summation is: 1 + 2 + 4 + 5 + 10 = 22.

Input Format

Natural number n


n should be positive

Output Format

Divisor summation of n

Sample Input 0


Sample Output 0

Divisor summation is 22

Sample Input 1


Sample Output 1

Invalid natural number

Refer : C Programming HackerRank all solutions for Loops | Arrays | strings




void divisor(int n)
    int sum=0,i;
    printf("Divisor summation is %d\n",sum);

int main() {

    int n;
        printf("Invalid natural number\n");
    return 0;


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Input (stdin)

Your Output (stdout)

Divisor summation is 22
Expected Output

Divisor summation is 22


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