(HackerRank) Write a Modular C Programming code to solve Find ODD 1, All elements in an array occurs even number of times, except one element. Find the element which occurs odd number of times.
All elements in an array occur an even number of times, except one element. Find the element which occurs odd number of times.
Input Format
First-line contains ‘N’, number of array elements followed by ‘N’ elements separated by a space in the next line
Constraints
N>0 and N<=10^4
-10^5<=a[i]<=10^5
Output Format
Output the element occurring odd number of times.
Sample Input 0
-1
Sample Output 0
Invalid
Sample Input 1
9
1 2 3 1 3 4 2 2 4
Sample Output 1
2
Explanation 1
We clearly see that all elements occurs even number of times except 2
Refer : C Programming HackerRank all solutions for Loops | Arrays | strings
CODE:
#include<stdio.h> #include<stdlib.h> #include<string.h> #include<math.h> int main() { int n; scanf("%d",&n); if(n>0) { int array[n],i,j,count; for(i=0;i<n;i++) { scanf("%d",&array[i]); } for(i=0;i<n;i++) { count=0; for(j=0;j<n;j++) { if(array[i]==array[j]) count++; } if(count%2!=0) { printf("%d",array[i]); break; } } } else{ printf("Invalid"); } return 0; }
OUTPUT
Congratulations, you passed the sample test case. Click the Submit Code button to run your code against all the test cases. Input (stdin) -1 Your Output (stdout) Invalid Expected Output Invalid
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