C Programming – HackerRank Solution | Reverse Words 11 |

(HackerRank) Write a Modular C Programming code to solve Reverse Words 11, Given a String S, reverse the string without reversing its individual words. Words are separated by dots.

Given a String S, reverse the string without reversing its individual words. Words are separated by dots.

Input Format

First line contains a string separated by dot between individual words.

Constraints

1 <= |S| <= 2000

Output Format

Display the output string in one line

Sample Input 0

i.like.this.program.very.much

Sample Output 0

much.very.program.this.like.i

Explanation 0

Take each word from the end and add the same to the string at the beginning. Note that each word is separated by a dot.

Refer : C Programming HackerRank all solutions for Loops | Arrays | strings

 

CODE:

#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#include<math.h>

int main() {
    char str[100],temp;
    scanf("%s",str);
    int dots=0,i,j,s,l;
    l=strlen(str);
    for(i=0;i<l/2;i++)
    {
        temp=str[i];
        str[i]=str[l-1-i];
        str[l-1-i]=temp;
    }
   // printf("%s\n",str);
    i=0;
    while(str[i])
    {
        if(str[i]==46)
            dots++;
        i++;
    }
    s=0;
    for(j=0;j<dots;j++)
    {
        i=s;
        while(str[i]!=46)
        {
            i++;
        }
        l=i;
        for(i=0;i<((l-s)/2);i++)
        {
        temp=str[s+i];
        str[s+i]=str[l-1-i];
        str[l-1-i]=temp;
        }
        s=l+1;
    }
    l=strlen(str);
        for(i=0;i<(l-s)/2;i++)
        {
        temp=str[s+i];
        str[s+i]=str[l-1-i];
        str[l-1-i]=temp;
        }
    printf("%s",str);
    return 0;
}

OUTPUT

Congratulations, you passed the sample test case.

Click the Submit Code button to run your code against all the test cases.

Input (stdin)

i.like.this.program.very.much
Your Output (stdout)

much.very.program.this.like.i
Expected Output

much.very.program.this.like.i

 

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