Write a Modular C Programming code to find out the efficiency of the worker
In a company, worker efficiency is determined on the basis of the time required for a worker to complete a particular job. If the time taken by the worker is between 2-3 hours, then the worker is said to be highly efficient. If the time required by the worker is between 3-4 hours, then the worker is ordered to improve speed. If the time taken is between 4-5 hours, the worker is given the training to improve his speed, and if the time taken by the worker is more than 5 hours, then the worker is terminated.
The time taken by the worker is input through the keyboard; write a c program to find the efficiency of the worker.
Input Format
time to complete a job in hours and minutes (hh mm).
Constraints
0<=hh<=24 0<=mm<=59
Output Format
print work efficiency of worker
Sample Input 0
2 00
Sample Output 0
highly efficient
Sample Input 1
3 40
Sample Output 1
improve speed
Sample Input 2
4 45
Sample Output 2
training to improve speed
Sample Input 3
5 15
Sample Output 3
terminated
Sample Input 4
25 25
Sample Output 4
Invalid timeRefer : C Programming HackerRank all solutions for Loops | Arrays | strings
CODE:
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#include<math.h>
int main()
{
int h,m;
scanf("%d%d",&h,&m);
if(h>=0&&h<=24&&m>=0&&m<=59)
{
if(h>=2&&h<3&&m>=0&&m<=59)
printf("highly efficient");
else if(h>=3&&h<4&&m>=0&&m<=59)
printf("improve speed");
else if(h>=4&&h<5&&m>=0&&m<=59)
printf("training to improve speed");
else
printf("terminated");
}
else
printf("Invalid time");
}
OUTPUT
Congratulations, you passed the sample test case. Click the Submit Code button to run your code against all the test cases. Input (stdin) 2 00 Your Output (stdout) highly efficient Expected Output highly efficient
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